print "This is a program to help give you an idea which high-end PDA you should consider buying."
print "While there are any number of companies from which you might buy a PDA, this program considers only the 8 market leadersper IDC. "
print "The program will ask you to input a ranking or weighting for a number of criteria"
print "that may be of importance in to you in choosing your next PDA. When prompted, please type in a number from 1 to 100 for each criteria, with"
print "100 being of utmost importance to you, and 1 being of almost no importance to you."
def get_list(heading, prompt):
        """ get_list(heading, prompt) -> list

This function prompts for a list of things.  The heading is printed on
a line by itself, and the prompt must have a %d substitution for the
number of the item within the list.
"""
        print heading
        print
        print "(enter a blank line to end the list)"
        ret = []
        i = 1
        while 1:
                line = raw_input(prompt % i)
                if not line:
                        break
                ret.append(line)
                i=i+1
        print
        return ret

def get_number(prompt):
        """ get_number(prompt) -> float

This function prompts for a number.  If the user enters bad input, such as
"cat" or "3l", it will prompt again.
"""
        res = None
        while res is None:
                try:
                        res = float(raw_input(prompt))
                except ValueError: pass
        return res


options = ["Sharp", "Compaq", "HP", "Sony", "Palm", "Handspring", "Casio", "Research in Motion"]
criteria = ["computing power", "expandability", "size of existing user base", "ease of cell phone integration", "breadth of tools for developers", "cool factor", "cost or price?", "bluetooth and/or wireless capabilities"]


rankings = {}
print
print "Enter relative importance of criteria (higher is more important)"
print
for c in criteria:
                rankings[c] = get_number("Criterion %s: " % c)

# Next, get the user to score each option on all the criteria.
# Here, we index the dictionary on the pair (option, criterion). 
# This is similar to a two-dimensional array in other languages

score = {("Sharp", "computing power"):100, ("Sharp", "expandability"):100, ("Sharp", "size of existing user base"):20, ("Sharp", "ease of cell phone integration"):20, ("Sharp", "breadth of tools for developers"):100, ("Sharp", "cool factor"):100, ("Sharp", "cost or price?"):80, ("Sharp", "bluetooth and/or wireless capabilities"):50,
("Compaq", "computing power"):100, ("Compaq", "expandability"):50, ("Compaq", "size of existing user base"):50, ("Compaq", "ease of cell phone integration"):20, ("Compaq", "breadth of tools for developers"):50, ("Compaq", "cool factor"):50, ("Compaq", "cost or price?"):100, ("Compaq", "bluetooth and/or wireless capabilities"):100,
("HP", "computing power"):100, ("HP", "expandability"):80, ("HP", "size of existing user base"):30, ("HP", "ease of cell phone integration"):20, ("HP", "breadth of tools for developers"):50, ("HP", "cool factor"):50, ("HP", "cost or price?"):100, ("HP", "bluetooth and/or wireless capabilities"):100,
("Sony", "computing power"):80, ("Sony", "expandability"):80, ("Sony", "size of existing user base"):30, ("Sony", "ease of cell phone integration"):50, ("Sony", "breadth of tools for developers"):50, ("Sony", "cool factor"):30, ("Sony", "cost or price?"):80, ("Sony", "bluetooth and/or wireless capabilities"):100,
("Palm", "computing power"):20, ("Palm", "expandability"):75, ("Palm", "size of existing user base"):100, ("Palm", "ease of cell phone integration"):10, ("Palm", "breadth of tools for developers"):30, ("Palm", "cool factor"):10, ("Palm", "cost or price?"):10, ("Palm", "bluetooth and/or wireless capabilities"):100,
("Handspring", "computing power"):50, ("Handspring", "expandability"):100, ("Handspring", "size of existing user base"):70, ("Handspring", "ease of cell phone integration"):100, ("Handspring", "breadth of tools for developers"):10, ("Handspring", "cool factor"):50, ("Handspring", "cost or price?"):10, ("Handspring", "bluetooth and/or wireless capabilities"):100,
("Casio", "computing power"):15, ("Casio", "expandability"):50, ("Casio", "size of existing user base"):50, ("Casio", "ease of cell phone integration"):10, ("Casio", "breadth of tools for developers"):1, ("Casio", "cool factor"):1, ("Casio", "cost or price?"):10, ("Casio", "bluetooth and/or wireless capabilities"):1,
("Research in Motion", "computing power"):10, ("Research in Motion", "expandability"):10, ("Research in Motion", "size of existing user base"):10, ("Research in Motion", "ease of cell phone integration"):100, ("Research in Motion", "breadth of tools for developers"):1, ("Research in Motion", "cool factor"):100, ("Research in Motion", "cost or price?"):10, ("Research in Motion", "bluetooth and/or wireless capabilities"):100,}


# Calculate the resulting score for each option.  
# The "result" dictionary is indexed with the names of the options.
result = {}
for o in options:
        value = 0
        for c in criteria:
                
                value = value + rankings[c] * score[o, c]
        result[o] = value

# Now, I want to take the dictionary result, and turn it into a ranked list

results = result.items()        # A list of tuples (key, value)
results.sort(lambda x, y: -cmp(x[1], y[1]))
                                # Sort the list using the reverse of the
                                # "value" of the entry, so that higher
                                # values come first

print
print "Results, in order from highest to lowest score"
print
print "%5s %s" % ("Score", "Option")

# Take the pairs out of results in order, and print them out
for option, result in results:
        print "%5s %s" % (result, option)



award = result
winner = option
for option,result in results:
        if result > award:
                award = result
                winner = option
print "Go ahead and buy a %s !!!" % winner